Drops of liquid of density are floating half immersed in a liquid of density . If the surface tension of the liquid is T, then the radius of drop will be :
In old age arteries carrying blood in the human body become narrow resulting in an increase in the blood pressure. This follows from
Pascal's law
Stokes's law
Bernoulli's principle
Archimedes' principle
The ratio of the terminal velocities of two drops of radii R and R/2 is
2
1
1/2
4
A 20 cm long capillary tube is dipped in water. The water rises up to 8 cm. If the entire arrangement is put in a freely falling elevator the length of water column in the capillary tube will be
4 cm
20 cm
8 cm
10 cm
A man is sitting in a boat, which is floating on a pond. If the man drinks some water from the pond, the level of water in the pond.
decreases
increases
remains unchanged
may increase or decrease depending on the weight of the man
The radii of two drops are in the ratio of 3 : 2, their terminal velocities are in the ratio
9 : 4
2 : 3
3 : 2
2 : 9
A wooden block, with a coin placed on its top, floats in water as shown in figure. The distance l and h are shown here. After some time the coin falls into the water. Then
l decreases and h increases
l increases and h decreases
both l and h increase
both l and h decrease
Water rises in a capillary tube upto a height of 10 cm whereas mercury depresses in it by 3.42 cm. If the angle of contact and density of mercury are 135o and 13.6 gm/cc respectively, then the ratio of the surface tension of water and mercury will be :
6.5 : 1
1 : 6.5
1 : 5.6
5.6 : 1
Spherical balls of radius R are falling in a viscous fluid of viscosity η with a velocity v. The retarding viscous force acting on the spherical ball is
directly proportional to R but inversely proportional to v
directly proportional to both radius R and velocity v
inversely proportional to both radius R and velocity v
inversely proportional to radius R and directly proportional to velocity v.
Water from a tap emerges vertically downwards with an initial speed of 1.0 ms-1 . The cross-sectional area of the tap is 10-4 m2. Assume that the pressure is constant throughout the stream of water, and that the flow is steady. The cross-sectional area of the stream 0.15 m below the tap is
5.0×10-4 m2
1.0×10-5 m2
5.0×10-5 m2
2.0×10-5 m2
