A particle starts S.H.M from the mean position. Its amplitude is A and time period is T. At the time its speed is half of the maximum speed. Its displacement y from the mean position is:
When a damped harmonic oscillator completes 100 oscillations, its amplitude is reduced to of its initial value. What will be its amplitude when it completes 200 oscillations ?
A particle moves such that its acceleration a is given by a = -bx where x is the displacement from equilibrium position and b is a constant. The period of oscillations is:
A particle executes simple harmonic motion with a frequency f. The frequency with which kinetic energy oscillates is:
f
4 f
2 f
f/2
When a long spring is stretched by 2 cm., its potential energy is U. If the spring is stretched by 10 cm, the potential energy in it will be:
10U
25U
5U
Two simple pendulums of length 0.5m and 2.0m respectively are given small linear displacement in one direction at the same time. They will again be in the same phase when the pendulum of shorter length has completed oscillations:
5
1
2
3
If metal bob of a simple pendulum is replaced by a wooden bob, then its time period will:
Increase
Decrease
Remain the same
First increases then decreases
A point particle of mass 0.1 kg is executing S.H.M of amplitude 0.1 m. When the particle passes through the mean position, its K.E is 8 x 10-3 J. The equation of motion of this particle if its initial phase of oscillations is 45o is:
A hollow sphere filled with water forms the bob of a simple pendulum. A small hole at the bottom of the bob allows the water to slowly flow out as it is set into small oscillations and its period of oscillations is measured. The time period will :
Remain constant
First increases , then decreases
A spring has a certain mass suspended from it and its period of vertical oscillations is T. The spring is now cut into two halves and the same mass is suspended from one of the halves. Find out the period of vertical oscillation ?
2 T
T/2