Log 2x > 4, then x belongs to
x > 4
x > 16
x > 8
None of these
( x - 1 ) > 0
( x -2 ) > 0
(x - 2 ) < 0
( x - 1 ) > 0 if ( x -2 ) > 0
If x satisfies the inequations 2x - 7 < 11, 3x + 4 < -5, then x lies in the interval
(-∞, -3)
(-∞, 3)
(-∞, 2)
(-∞, ∞)
The set of values of x satisfying the inequalities ( x -1 ) ( x -2 ) < 0 and ( 3x - 7 ) ( 2x - 3 ) > 0 is
(1, 2 )
( 2, 7/3 )
( 1, 7/3 )
( 1, 3/2 )
If x2 > 4, then
x > 2
| x | > 2
-2 < x < 2
If |x| > 5, then
0 < x < 5
x < -5 or x > 5
-5 < x < 5
x > 5
x2 -3 |x| + 2 < 0, then x belongs to
( 1,2 )
( -2, -1 )
( -2, -1 ) U ( 1, 2 )
( -3, 5 )
If a > b then
a + 5 > b + 5
a - b < b - 5
a + b < b + b
Depends on a and b
|3x + 7 | < 5, then x belongs to
( -4, -3 )
( -4, -2/3 )
(-5, 5)
( -5/3, 5/3 )
If a/b < c/d, then
( a/b)2 < (c/d)2