A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is:
The potential energy of a simple harmonic oscillator when the particle is half way to its end point is:
A body of mass 5 kg hangs from a spring and oscillates with a time period of 2 seconds. If the body is removed, the length of the spring will decrease by:
2 metres
g metres
g/k metres
k/g metres
When a damped harmonic oscillator completes 100 oscillations, its amplitude is reduced to of its initial value. What will be its amplitude when it completes 200 oscillations ?
A body executes SHM with an amplitude . At what displacement from the mean position is the potential energy of the body is one-fourth of its total energy ?
Some other fraction of a
A system exhibiting S.H.M. must possess:
Elasticity as well as inertia
Elasticity only
Inertia only
Elasticity, inertia and external force
The acceleration of a particle in S.H.M. is:
Always constant
Maximum at extreme positions
Maximum at mean position
Always zero
A particle is performing simple harmonic motion along the x axis with amplitude 4 cm and time period 1.2 sec. The minimum time taken by the particle to move from x = + 2 cm to x = + 4 cm and back again is:
0.4 s
0.3 s
0.2 s
0.6 s
A particle is executing S.H.M of amplitude 4 cm and T = 4 sec. The time taken by it to move from positive extreme position to half the amplitude is:
1 sec
1/3 sec
2/3 sec
A body is executing SHM. When the displacements from the mean position is 4 cm and 5 cm, the corresponding velocities are 10 cm/s and 8cm/s. Then the time period of the body will be :