A particle executes simple harmonic motion of amplitude A. At what distance from the mean position its kinetic energy is equal to its potential energy ?
0.51 A
0.61 A
0.71 A
0.81 A
A particle starts simple harmonic motion from the mean position. Its amplitude is a and time period is T. What is its displacement when its speed is half of its maximum speed ?
Two simple pendulums of length 0.5m and 2.0m respectively are given small linear displacement in one direction at the same time. They will again be in the same phase when the pendulum of shorter length has completed oscillations:
5
1
2
3
A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the increase in the time period is:
21%
10%
30%
50%
A rectangular block of mass m and the area of cross-section A floats in a liquid of density .If it is given a small vertical displacement from equilibrium it undergoes oscillation with a time period T. Then:
A point particle of mass 0.1 kg is executing S.H.M of amplitude 0.1 m. When the particle passes through the mean position, its K.E is 8 x 10-3 J. The equation of motion of this particle if its initial phase of oscillations is 45o is:
A particle moves such that its acceleration a is given by a = -bx where x is the displacement from equilibrium position and b is a constant. The period of oscillations is:
Two springs A and B have force constants KA and KB such that kB =2kA. The four ends of the springs are stretched by the same force. If the energy stored in spring A is E, then the energy stored in spring B will be:
2E
E
4E
Which one of the following is a simple harmonic motion ?
Ball bouncing between two rigid vertical walls
Particle moving in a circle with uniform speed
Wave moving through a string fixed at both ends
Earth spinning about its own axis
A particle is subjected to two mutually perpendicular simple harmonic motions such that is x and y coordinates are given byThe path of the particle will be:
A straight line
A circle
An ellipse
A parabola