If the points with position vectors are collinear, then a is equal to
-40
-20
20
40
Let and , are non - zero and non- collinear vectors. If there exists scalars α, β such that α + β = , then
α = β ≠ 0
α + β = 0
α = β = 0
α = β
If the position vector of A with respect to O is then the position vector of B with respect to 0 is
The position vectors of P and Q are respectively and . If R is a point on such that , then the position vector of R is
If C is the midpoint of AB and P is any point outside AB, then
The non-zero vectors Then, the angle between is.
π
0
π/4
π/2
If , , are three vectors such that = + and the angle between and is π/2, then
a2 = b2 + c2
b2 = c2 + a2
c2 = a2 + b2
2a2 - b2 = c2
If then angle between and is
π/6
π/3
Given, , then x, y, z are respectively.
Consider points A,B,C and D with position vector respectively. Then, ABCD is a.
Square
Rhombus
Rectangle
None of these
