If Z1 = √2 ( cos π/4) and z2 = √3 (cos π/3 + i sin π/3 ) then |z1z2| is
6
√2
√6
√3
The argument of the complex number is
π/3
π/4
π/5
π/6
Express in the standard form of (a+ib):
None of these
The additive inverse of 1 - i is
0 + 0i
-1 + i
The modulus of is
2
3
If z is a complex number such that Re(z) = Im (z) , then
Re (Z2) = 0
Im (z2) = 0
Re (z2) = Im (z2)
z2 = 0
If x = 3 + i, then x3 - 3 x2 - 8 x + 15 is equal to
10
45
-15
The real values of x and y for which the equation is satisfied (1-i) x + (1+i) y = 1-3 i
2, -1
-2, -1
-2, 1
2,1
Find the real and imaginary part of (2+i) (3-2 i)
8,1
-8,1
8,-1
-8,-1
The real part of the complex number is
1/5
-1/5
5
2/5
