2
-2
1
0
[2, 3]
[3, 4]
[2, 4]
(2, 4)
, then
α = 1
α = 0
α = -1
None of these
Δ = 0
Δ = 2 abc
Δ = -abc
Δ = a2 + b2 + c2
The solution set of the equation is
{1, 2}
{-1, 2}
{1, -2}
{-1, -2}
abc
a + b +c
The value of is
(a + b) (b + c) (c + a)
4 abc
The value of the determinant is
∞
ω
If 1, ω , ω2 are the cube roots of unity, then
ω2