The solution of the equation | z | - z = 1 + 2i is
2 - 3/2 i
3/2 + 2i
3/2 - 2i
-2 + 3/2 i
If z = 1 + i , then the multiplicative inverse of z2 is (where i = √-1 )
2 i
1 - i
-i/2
i/2
The polar form of complex number 1 + i is
√2 (cos π/4 + i sin π/4 )
√2 (cos 2π/4 + i sin 2π/4
√2 (cos π/4 - i sin π/4 )
√3 (sin 2π/4 + i cos 2π/4)
If conjugate and reciprocal of a complex number z = x + iy are equal , then
x + y = 1
x2 + y2 = 1
x = 1 and y = 0
x = 0 and y = 1
If P is a multiple of n , then the sum of Pth power of nth roots of unity is
p
n
0
None of these
a = 0 and b = 1
a = 1 and b = 0
a = 2 and b = -1
a = -1 and b = 2
(x = 3, y = 1 )
(x = 1, y = 3 )
(x = 0 , y = 0 )
If we express ( 2 + 3 i ) 2 in the form of ( x + iy ) , we get
-5 + 12 i
12 - 5 i
5 - 12 i
12 + 5 i
If the complex numbers z1,z2 and z3 represent the vertices of an equilateral triangle such that | z1 | = | z2 | = | z3 | , then the sum of z1,z2 and z3 is
-1
1
2