If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0m/s2 at any time, the angular frequency of the oscillator is equal to
10 rad/s
0.1 rad/s
100 rad/s
1 rad/s
A hollow sphere filled with water forms the bob of a simple pendulum. A small hole at the bottom of the bob allows the water to slowly flow out as it is set into small oscillations and its period of oscillations is measured. The time period will
increase
decrease
remain constant
first (a), then (b)
A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the increase in the time period is
21%
10%
30%
50%
A wave has SHM (simple harmonic motion) whose period is 4 s while another wave which also possesses SHM has its period 3 s. If both are combined, then the resultant wave will have the period equal to
4 s
5 s
12 s
3 s
Two simple pendulums having lengths 0.5 m and 2.0 m are displaced linearly a little at the same time. They will be in the same phase when shorter pendulum completes oscillations equal to
2
5
3
1
A point performs simple harmonic oscillation of period T and the equation of motion is given by After the elapse of what fraction of the time period the velocity of the point will be equal to half of its maximum velocity ?
The total energy of a body performing S.H.M. depends on
k,a,m
k,a,x
k,a
k,x
A simple pendulum with a bob of mass m oscillates from A to C and back to A such that PB is H. If the acceleration due to gravity is g then velocity of the bob as it passes through B is
zero
2gH
mgH
The displacement x (in metres) of a particle performing S.H.M is related to time t (in second) as :
0.5 Hz
1.0 Hz
1.5 Hz
2.0 Hz
A body is executing S.H.M When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocities are 10 cm/sec and 8cm/sec. Then time period of the body is
