Two spherical bodies of mass M and 5M and radii R and 2R respectively are released in free space with initial separation between their centres equal to 12R. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is :

A satellite is revolving round the earth. Its K.E is E_k. How much would it be made so that the satellite may escape out of the gravitational field of earth?

The time period of a satellite of earth is 5h. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become :

A satellite moves eastwards very near the surface of the earth in the equatorial plane of the earth with speed v₀. Another satellite moves at the same height with the same speed in the equatorial plane but westwards. If R is the radius of the earth and ω be its angular speed about its own axis, then the difference in the two time period as observed on the earth will be approximately equal to :

A planet of mass M is revolving round the sun of mass M_s in an elliptical orbit. The maximum and minimum distance of the planet from sun are r₁ and r₂ respectively. Then :

If the radius of the earth decreases by 10%, the mass remaining unchanged, what will happen to the acceleration due to gravity?

The kinetic energy needed to project a body of mass m from the earth's surface (radius R) to infinity is :

The radius of earth is 6400 km and the value of g is 10m/s² . If the weight of 5km body on the equator becomes zero, then the angular speed of earth will be :

The time period of an earth satellite in circular orbit is independent of :

An infinity number of point masses each equal to m are placed at x = 1, x = 2, x = 4, x = 8, ..... What is the total gravitational potential at x - 0?