Domain of f (x) = is
R - { -2, 2 }
R - {-1, 1 }
R - { 2 }
R
Let f: R →R be a function defined by
f( x ) = 2 x + 1. Then f -1 is
x -1
(x - 1)/2
x + 1
(x + 1)/2
The function f : R → R defined by f ( x ) = x + 1 is
Injective
Bijective
Inverse
Identity
None of these
Let f, g: R → R be defined by f( x ) = 2 x + 1 and g ( x ) = x -1/2, then gof =
x
2 x
The function f(x) = is.
Even
Odd
Neither even nor odd
When f (-1) = 3, the polynomial function f (x) of the second degree is
a + b = 1
a + b + c = -3
a - b + c = 3
a - b - c = 3
If f(x) = x + 1/x , then which of the following is correct?
[ f (x) ]3 = f (x)3 + 3 f (x)
[ f (x) ] 3 = f (x)3 - 3 f (1/x)
[ f (x) ]3 = f (x 3 )+ 3 f (1/x)
f (x)3 = (f [x])3 - 3 f (x)
Let A = { 1, 2}, B = { 3, 4 } and C = { 5, 6 } and F : A → B and g : B → C Such that f ( 1 ) = 3, f ( 2 ) = 4, g ( 3 ) = 5, g ( 4 ) = 6, then go f =
{ (1, 3 ) ( 2, 4 )}
{ (1, 5), ( 2, 6 )}
{ (, 2 ) ( 5, 6 ) }
{ ( 3, 5 ) ( 4, 6 ) }
Range of f (x) = is
(0, ∞ )
(0, 5 )
(5, ∞ )
(-5, 5 )
