Solution of tan-12x + tan-1 3 x = π/4
-1 or 1/6
1 or -1/6
-1 or 6
1 or -6
tan (735o) = tan (2 × 360o + 15o)
Sin 35o
Cos 15o
tan 15o
cot 15o
The product s(s-a) (s-b) (s-c) is equal to
Δ
Δ2
2 Δ
Δ/s
cos 15o =
tan-1 (1/7) + tan-1 (1/13) =
tan-1(1/9)
tan-1 (20)
tan-1(2/9)
tan-1(3/4)
The principal value of sin-1 (1/2)
π
π/2
π/6
0
The value of is
3/16
3/8
3/4
1/2
Sin (1/2 cos-1 4/5)
If sin-1 (1/2) = tan-1 x, find the value of x
√3
If sin θ = 3/8 and θ is acute, find sin 2 θ