Two bodies with kinetic energies in the ratio 4 : 1 are moving with equal linear momentum. The ratio of their masses is

A position dependent force F=(7–2x + 3x²) N acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m.

Work done in joule is

If kinetic energy of a body is increased by 300% then the percentage change in momentum will be

An engine pumps water continuously through a hose. Water leaves the hose with a velocity v and m is the mass per unit length of water jet. What is the rate at which kinetic energy is imparted to water? 

A particle of mass m₁ is moving with a velocity v₁ and another particle of mass m₂ is moving with a velocity v₂. Both of them have the same momentum but their different kinetic energies are E₁ and E₂ respectively. If m₁> m₂, then

A force F acting on an object varies with distance x as shown here. The force is in newton and x is in metre. The work done by the force in moving the object x = 0 to x = 6m is

300 J of work is done in sliding a 2kg block up an inclined plane of height 10 m. Taking g = 10 m/s², work done against friction is

The KE acquired by a mass m in traveling a certain distance d, starting from rest, under the action of a constant force is directly proportional to  

A body of mass 1kg is thrown upward with a velocity 20 ms^-1.It momentarily comes to rest after attaining a height of 18m. How much energy is lost due to air friction ? ( g = 10 ms^-2)  

A body of mass m moving with velocity 3 km/h collides with a body of mass 2.m at rest. Now the coalesced mass starts to move with a velocity