____________=1+tan2θ
cos2θ
sec2θ
cosec2θ
cot2θ
Sinθ*cosecθ = ____________
1
0
180
none
If cos θ = -5/12 in which quadrant does θ lie ?
I quadrant
II quadrant
III quadrant
II or III
tanθ tan(90-θ)= ___________
2
3
If sec2 θ = 4/3, the general value of θ is
2 n π ± π/6
n π ± π/6
2 n π ± π/3
n π ± π/3
Sec2A + cosec2A =
(sec A+ cosec A)2
(secA-cosecA)2
sec2A. cosec2A
sec2A/cosec2A
If θ =π/4, then 1+ tan 2 θ =
sin 2 θ
cot 2 θ
cosec2 θ
sec 2 θ
(1+ tanA)2 + (1-tanA)2 =
sec2A
secA
2sec2A
Cosecθ = 1/_
Cosθ
Sinθ
tanθ
Cotθ
1 - cos2θ - sin2θ = ___________
