Sinθ*cosecθ = ____________
1
0
180
none
____________=1+tan2θ
cos2θ
sec2θ
cosec2θ
cot2θ
If θ =π/4, then 1+ tan 2 θ =
sin 2 θ
cot 2 θ
cosec2 θ
sec 2 θ
If cos θ = -5/12 in which quadrant does θ lie ?
I quadrant
II quadrant
III quadrant
II or III
(1+ tanA)2 + (1-tanA)2 =
sec2A
secA
2sec2A
sin θ
-sin θ
cos θ
- cos θ
The general solution of sinx - 3 sin 2x+ sin 3x= cosx -3 cos2x + cos 3 x is
n π+ π/8
n π/2+ π/8
(-1)n(nπ/2)+π/8
2nπ+cos-1 (3/2)
If sec2 θ = 4/3, the general value of θ is
2 n π ± π/6
n π ± π/6
2 n π ± π/3
n π ± π/3
tanθ tan(90-θ)= ___________
2
3
1 - cos2θ - sin2θ = ___________
