The cartesian equation of the line which passes through the point (-2, 4, -4) and parallel to the line given by is
Find the vector equation for the line passing through the point (-1, 0, 2) and (3, 4, 6) is
The co ordinates of the point where the line through A(5, 1, 6) and B (3, 4, 1) cross the yz - plane
(17/2, 0, -13/2)
(0, 0, -13/2)
(17/2, 0, 1)
(0, 17/2, -13/2)
The cartesian equation of a line are 6x - 2 = 3y + 1 = 2z - 2. Find the vector equation of this line
A line passes through the point (2, -1, 3) and is Perpendicular to the line findits equation
The Cartesian equations of a line are 6x - 2 = 3y + 1 = 2z - 2, then direction ratios are
6, 3, 2
1, 2, 3
2, 3, 4
6, 3, 4
The value of λ for which the point A(2, 1, 3), B(5, 0, 5) and C(-4, λ, -1) are collinear is
1
2
3
4
Find the equation of a line in cartesian form passes through the vector
Equation of the line passing through the point (2, 3, 4) and (4, 6, 5) is
