In the figure ABCD is a parallelogram and AEB is a triangle. If ar ||gm ABCD = 172.6 sq.cm Then ar ΔAEB =
86.3 sq.cm
172.6 sq.cm
354.2 sq.cm
Cannot be determined
If ar (ΔABC) = ar (ΔDBC), then which of the following is always true?
AD || BC
Area (AOD) = area (BOC)
∠AOD = 90°
AB > DC
Which of the following does not show two quadrilaterals on same base?
In the given figure AB||DC. Which the following is true about the figure.
Area AOD = area BOC
Area AOB = area DOC
Area ADC = area ABC
None of these
ABCD is ||gm. O is an interior point. If area (ΔAOB) + area (ΔDOC) = 43. sq. units. Then area (||gm ABCD) =
172 sq.units
123 sq.units
143 sq.units
86 sq.units
In the given figure, D is midpoint of ΔABC. If ar ΔABC = (2x2 - 2)units, then ar ΔABD =
(x - 1)2
(x + 1)2
2(x - 1) (x + 1)
(x + 1) (x - 1)
Find the area of the given parallelogram.
600 cm2
240 cm2
300 cm2
230 cm2
ABCD is a parallelogram. If area (AOB) = 17.5 sq. units then area ||gm ABCD =
140 sq. units
35 sq.units
68 sq.units
70 sq. units
If D is midpoint of BC and area ΔABD = 1/√2 sq.units, then area ΔABC is
1/√2 sq. units
√2 sq. units
2 sq.unit
Which of the following statement is correct.
Area (ABCD) = area (ABCDE)
Area (ABCD) = area (BCDE)
Area (ABDE) = area (BCD)