In the adjoining figure, AC = ________
25 m
Cos2θ
tan2θ
Sin2θ
Cot2θ
9 tan2θ - 9 Sec2θ =
1
0
9
-9
(1 - Cos2θ) (1 + Cot2θ)
If Cosθ = Sin θ, then θ =
30
60
45
35
In the adjoining figure, Sinθ = . Then BC =
85 m
65 m
95 m
15 m
13
25
Sin (90 - θ) Cos θ + Cos (90 - θ) Sinθ =
2
-1