Cos4 A - Sin4 A =
2 Sin2 A - 1
1 - 2 Sin2 A
2 Cos2 A - 1
1 -2 Cos2 A
The value of is
0
2
3
1
If sin θ = 3/8 and θ is acute, find sin 2 θ
ΔABC is right angled at C, then tan A + tan B is equal to.
a + b
In a ΔABC, ∠A = π/2, then cos2 B + cos2 C equals
-2
-1
Sin (cos-1 (3/5) =
1/5
3/4
4/5
1/3
Area of Δ ABC is
1/2 ab cos C
1/2 ab sin c
1/2 ab cos B
1/2 ca sin B
tan-1 (1/7) + tan-1 (1/13) =
tan-1(1/9)
tan-1 (20)
tan-1(2/9)
tan-1(3/4)
Sin (1/2 cos-1 4/5)
The product s(s-a) (s-b) (s-c) is equal to
Δ
Δ2
2 Δ
Δ/s