When a hydrogen atom is raised from the ground state to an excited state.
PE decreases and KE increases
PE increases and KE decreases
Both KE and PE decreases
Absorption spectrum
Energy E of a hydrogen atom with principal quantum number n is given by .The energy of a photon ejected when the electron jumps from n = 3 state to n = 2 state of hydrogen,is approximately
1.5 eV
0. 85 eV
3.4 eV
1.9 eV
The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is
6.8 eV
10.2 eV
Zero
The ionization energy of hydrogen atom is 13.6 eV. Following Bohr’s theory, the energy corresponding to a transition between 3rd and 4th orbit is
3.40 eV
1.51 eV
0.85 eV
0.66 eV
Which source is associated with a line emission spectrum ?
Electric fire
Neon street sign
Red traffic light
Sun
In Rutherford scattering experiment, what will be the correct angle for α- scattering for an impact parameter, b = 0 ?
90o
270 o
0o
180o
In terms of Bohr radius α0, the radius of the second Bohr orbit of a hydrogen atom is :
4 α0
8 α0
√ 2 α0
2 α0
Which of the following transitions gives photon of maximum energy ?
n = 1 to n = 2
n = 2 to n = 1
n = 2 to n = 6
n = 6 to n = 2
Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr’s theory, the spectral lines emitted by hydrogen will be :
2
3
4
1
The ground state energy of H – atom is 13. 6 eV. The energy needed to ionize H – atom from its second excited state
13.6 eV
12.1 eV