log2 40 - log25 =
1
3
2
0
Log2 16 =
4
8
6
log3(1 + 1/3) + log3 (1 + 1/4) + ......log3 (1 + 1/80) =
If loga √2 = 1/6, then a
The logarithm of 5832 to the base 3√2 is
5
18
7
If log5a = 3, then value of a is
15
125
25
100
The logarithmic form of 7-1 = 1/7 is
log7 1/7 = -1
llog7 - 1 = 1/7
log-1 7 = 1/7
log1/7 - 1 = 7
log ab - log |b| =
loga
- loga
None of these
The exponential form of log1/3 1/27 = 3 is
(1/3)3 = 27
(1/27)3 = 1/3
(1/3)3 = 1/27
If loga[1 + logb {1 + logc x}] = 0, then x =
abc
a/bc