Find three consecutive numbers such that the sum of the second and third numbers exceeds the first by 14.
11, 12, 13
18, 19, 20
17, 18, 19
20, 21, 22
Solve x + 1/7 = 3/7
2/7
2
-1/7
= 2/7
Solve 10 = x/3
13
7
30
10/3
The value of y if 30 = 6(8 + y) is
-3
3
5
-5
Solve x - 7 = -12
19
-19
Which number from 16, 21, 20, -20 satisfy the equation
16
21
20
-20
The value of x if x - 14 = -30 is
-16
14
-14
If 2(3x + 1) = 20 then 3x + 1 =
22
18
10
40
Solve A = bh for b.
A + h
A - h
A × h
A/h
Frame a question for "a number decreased by 10 is 40"
x + 10 = 40
10 - x = 40
x - 10 = 40
x - 10 = -40
