Equation of the line passing through the point (2, 3, 4) and (4, 6, 5) is
The value of p and q so that the points (p, q,1), (-1, 4, -2) and (0, 2, -1) are collinear.
-2, -2
2, 2
2, -2
0, 2
Find the vector equation of the line joining the points whose position vectors are
The equation of bisector of obtuse angle of x - 2y + 4 = 0 and 4x - 3y + 2 = 0 is.
(4 - √5 ) x - (3 - 2 √5) y + (2 - 4 √5 ) = 0
(4 + √5) x + (3 - 2 √5 )y + (2 - 4 √5) = 0
(4 - √5) x + (3 + 2 √5) y + (2 - 4 √5) = 0
(4 - √5) x - (3 + 2 √5 ) y - (2 - 4 √5 ) = 0
The shortest distance between the planes of lines whose equations are
8 units
9 units
10 units
11 units
A line passes through the point (2, -1, 3) and is Perpendicular to the line find its equation
The cartesian equation of the line is . The vector equation of the line is
The area of curve | x | + | y | = 1 is.
√2
1
√3
2
The equation of a line passing through the point(-1, 2, 3) and having direction ratios proportional to -4, 5, 6 is
None of these
The cartesian equation of a line are 6x - 2 = 3y + 1 = 2z - 2. Find the vector equation of this line.
