The solution of the equation (x + 1)2. dy/dx = xex is
(x + 1) y = (x + 1)ex + c(x + 1)
(x + 1)y = (x + 1)ex + c
(x + 1)y = ex + c(x + 1)
y = (x + 1)ex + c (x + 1)
The differential equation obtained on eliminating A and B from the equation y = A cos ωt + B sin ωt, is
y" = -ω2y
y" + y = 0
y"+y"=0
y" - ω2y = 0
The solution of differential equation x dy - y dx = 0 represents
Rectangular hyperbola
Circle whose center is at origin
Parabola whose vertex is at origin
Straight line passing through origin
The degree of the differential equation is
1
2
3
0
The differential equation for which y = a cosx + b sinx is a solution of
The solution of y' - y = 1 and y(0) = - 1 is given by y (x) is equal to
-1
-exp (-x)
-exp (x)
exp (x) - 2
The solution of the differential equation y dx - x dy = x2y dx is.
yex2 = cx2
ye - x2 = cx2
y = cxe - x2/2
e-x + e-y = c
The differential equation corresponding to y2 - 2ay + x2 = a2 by eliminating a is
(dy/dx)2 (x2 - 2y2) - 4 (dy/dx)xy - x2 = 0
(dy/dx)2 (y2 - 2x2) - 4.dy/dx . xy - x2 = 0
(dy/dx)2 . y2 - 4. dy/dx . xy - x2 = 0
(dy/dx)2(x2 - 2y2) - 4. dy/dx - x2 = 0
The solution of dy/dx = ex+y + x2 ey; y(0) = 0 is
The particular solution of edy/dx = x + 1 given that x = 0, y = 3 is
y = x log (x + 1) - x + 3
y = (x + 1) log (x + 1) - x + 3
y = (x + 1) log (x + 1) - x + 2
y = (x + 1) log (x + 1) - x + 1