Let f(x)= sec-1x + tan-1x. Then f(x) is real for
x∈[-1,1]
x∈R
x∈N
x∈ (-∝,-1) ∪(1, +∝)
Sin-1 x + sin-1 2x = π/3, then x is
The value of cos-1 √3/2 is
-π/6
π/6
π/3
-π/3
Sin (Sec-1 25/7) =
24/25
28/25
26/25
22/25
If sin-1 x = y then
o ≤ y ≤ π
-π/2 ≤ y ≤ π/2
π/2 ≤ y ≤ π/2
6/7
6/√13
√13/5
17/6
The value of sin-1 1/2 is
Sin-1 4/5 + 2 tan-1 1/3 =
π/4
π/2
0
Sin(π/3 - sin-1 (-1/2) is equal to
1/2
1/3
1/4
1