, then
α = 1
α = 0
α = -1
None of these
The value of the determinant is
a + b + c
0
1
abc
The solution set of the equation is
{1, 2}
{-1, 2}
{1, -2}
{-1, -2}
The value of is
2 i + 12
2 i - 12
-2 i - 12
-2 i + 12
2 Δ
3 Δ
6 Δ
Δ = 0
Δ = 2 abc
Δ = -abc
Δ = a2 + b2 + c2
(a + b) (b + c) (c + a)
4 abc
a + b + c - 3 abc
3 (a + b) (b + c) (c + a)
(a - b) (b - c) (c - a)
(a - b) (b - c) (c - a) (a + b + c)
[2, 3]
[3, 4]
[2, 4]
(2, 4)
