The value of is
20
-2
0
5
abc
(a + b) (b + c) (c + a)
4 abc
None of these
The value of the determinant is
1
(a - b ) ( b - c) (c - a)
2 Δ
3 Δ
6 Δ
[2, 3]
[3, 4]
[2, 4]
(2, 4)
then f (x) is divisible by
n2 + n
(n + 1)!
(n + 2)!
n! (n2 + n + 1)
a + b + c
If 1, ω , ω2 are the cube roots of unity, then
ω
ω2
x2 + 2
2
