The solution set of the equation is
{1, 2}
{-1, 2}
{1, -2}
{-1, -2}
The value of is
a + b + c - 3 abc
3 (a + b) (b + c) (c + a)
(a - b) (b - c) (c - a)
(a - b) (b - c) (c - a) (a + b + c)
2 Δ
3 Δ
6 Δ
0
then f (x) is divisible by
n2 + n
(n + 1)!
(n + 2)!
n! (n2 + n + 1)
Which one of the following determinants has its value as zero?
, then x equals
1, 1, 0
0, -1, 1
1, -1, 3
0, 0, 3
[2, 3]
[3, 4]
[2, 4]
(2, 4)
2 i + 12
2 i - 12
-2 i - 12
-2 i + 12
The value of the determinant is
-2
x2 + 2
2
None of these
1
