A line touches the circle x2 + y2 = 2 a2 and also the parabola y2 = 8 ax.Its equation is
y = ± x
y = ± (x + c)
y = ±( x + 2a)
y = ± ( x - 2a)
The equation of the directrix of the parabola x2 = -4ay is.
x + a = 0
x - a = 0
y + a = 0
y - a = 0
The equation of the parabola with focus at (0, 3) and the directrix y + 3 = 0 is.
y2 = 12 x
y2 = -12 x
x2 = 12 y
x2 = -12 y
The point on the parabola y2 = 8x whose distance from the focus is 8, has x co-ordinate as
0
2
4
6
The parabola y2 = 4ax passes through the point (2, -6) , then the length of its latus rectum is
18
9
16
The vertex of the parabola y2 = 4a (x - a) is
(a, 0)
(0, a)
(0, 0)
None of these
The latus rectum of the parabola x2 - 4x - 2y - 8 = 0 is.
8
1
The tangents at the points (at21, 2at1), (at22, 2at2) on the parabola y2 = 4ax are at right angles if
t1t2 = -1
t1t2 =1
t1t2 = 2
t1t2 = -2
Find the equation of the parabola with focus (2, 0) and directrix x = -2
y2 = 16x
y2 = 8x
y2 = 12x
The vertex of the parabola y2 = 4 ( x + 1)
(0, 1)
(0 , -1)
(1, 0)
(-1, 0)
