If D is midpoint of BC and area (ΔABC) = 20 sq.unit then area (Δ ABD) =

Quadrilateral formed by joining the midpoints of a rhombus is

ABCD is a cyclic quadrilateral ∠A : ∠C = 3 : 2 ∠B : ∠D = 4 : 1 then ∠D =

In the figure ABCD is a parallelogram and AEB is a triangle. If ar ||gm ABCD = 172.6 sq.cm Then ar ΔAEB =

The central angle of arc ABC is 220^o ∠ABC is

In a parallelogram if diagonals are equal in length then it is

One angle of a cyclic quadrilateral is 60^o.Then its opposite angle is

If M is the midpoint of hypotenuse PR of a right angled triangle PQR right angled at Q then.

The figure obtained by joining the mid points of the sides of a rhombus, taken in order, is

Two angles of a quadrilateral are 60^o and 70^o and other two angles are in the ratio 8 : 15 then the remaining two angles are