In the given figure, D is midpoint of ΔABC. If ar ΔABC = (2x2 - 2)units, then ar ΔABD =
(x - 1)2
(x + 1)2
2(x - 1) (x + 1)
(x + 1) (x - 1)
If BD = 12 cm, AL = 6 cm and CM = 4 cm. Then area (ABCD) =
60 sq.cm
30 sq.cm
90 sq.cm
120 sq. cm
Quadrilateral formed by joining the midpoints of a rhombus is
Rhombus
Square
Rectangle
None of these
One angle of a cyclic quadrilateral is 60o.Then its opposite angle is
130o
100o
300o
120o
Consecutive angles of a parallelogram are
Supplementary
Complementary
Equal
The figure obtained by joining the mid points of the sides of a rhombus, taken in order, is
A rhombus
A rectangle
A square
Any parallelogram
The central angle of arc ABC is 220o ∠ABC is
60o
65o
70o
75o
In the figure ABCD is a parallelogram and AEB is a triangle. If ar ||gm ABCD = 172.6 sq.cm Then ar ΔAEB =
86.3 sq.cm
354.2 sq.cm
172.6 sq.cm
Cannot be determend
ABCD is a cyclic quadrilateral ∠A : ∠C = 3 : 2 ∠B : ∠D = 4 : 1 then ∠D =
30o
36o
45o
90o
Three angles of a quadrilateral are 75o, 90o and 75o. The fourth angle is
95o
105o
