A, B, C, D are four points of a circle in the order. A and C are the end points of a diameter, then ∠ADB can be
160o
180o
90o
70o
One angle of a cyclic quadrilateral is 60o.Then its opposite angle is
130o
100o
300o
120o
In the figure ABCD is a parallelogram and AEB is a triangle. If ar ||gm ABCD = 172.6 sq.cm Then ar ΔAEB =
86.3 sq.cm
354.2 sq.cm
172.6 sq.cm
Cannot be determend
Two angles of a quadrilateral are 60o and 70o and other two angles are in the ratio 8 : 15 then the remaining two angles are
80o, 150o
90o, 140o
100o, 130o
110o, 120o
If BD = 12 cm, AL = 6 cm and CM = 4 cm. Then area (ABCD) =
60 sq.cm
30 sq.cm
90 sq.cm
120 sq. cm
If D is midpoint of BC and area (ΔABC) = 20 sq.unit then area (Δ ABD) =
40 sq. units
10 sq. units
5 sq. units
20 sq. units
In the given figure, D is midpoint of ΔABC. If ar ΔABC = (2x2 - 2)units, then ar ΔABD =
(x - 1)2
(x + 1)2
2(x - 1) (x + 1)
(x + 1) (x - 1)
The length of the complete circle is called its
Radius
Diameter
Circumference
None of these
Three angles of a quadrilateral are 75o, 90o and 75o. The fourth angle is
95o
105o
In a parallelogram if diagonals are equal in length then it is
Rhombus
Square
Rectangle
