The time period of an earth satellite in circular orbit is independent of :
both the mass and radius of the orbit
neither the mass of the satellite nor the radius of its orbit
the mass of the satellite
radius of its orbit
A satellite of mass m revolves around the earth of the radius R at a height x from its surface. It g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is :
gx
The weight of a body at earth surface is 700 g wt. What will be its weight on a planet whose mass is 1/7 that of earth and radius half that of earth?
300 g-wt
200 g-wt
400 g-wt
57.1 g-wt
Suppose the gravitational force varies inversely as the nth power of distance. Then the time period of a planet in circular orbit of radius R around the sun will be proportional to :
Rn
Two spherical bodies of mass M and 5M and radii R and 2R respectively are released in free space with initial separation between their centres equal to 12R. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is :
7.5 R
1.5 R
2.5 R
4.5 R
ge and gp are accelerations due to gravity on the surface of earth and a planet respectively. The radius and mass of the planet are double the radius and mass of earth. Then :
ge = gp
ge = 2gp
gp = 2ge
ge = √2gp
The time period of a satellite of earth is 5h. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become :
40h
20h
10h
80h
A planet of mass M is revolving round the sun of mass Ms in an elliptical orbit. The maximum and minimum distance of the planet from sun are r1 and r2 respectively. Then :
If the radius of the earth decreases by 10%, the mass remaining unchanged, what will happen to the acceleration due to gravity?
Decreases by 19%
Increases by 19%
Decreases by more than 19%
Increases by more than 19%
The kinetic energy needed to project a body of mass m from the earth's surface (radius R) to infinity is :
mgR
2mgR