Which one of the following equations of motion represents a simple harmonic motion ?
Acceleration =-k0 x + k1 x2
Acceleration = -k(x+a)
Acceleration = k(x+a)
Acceleration - kxwhere k,k0,k1 and a are all positive
A particle executes simple harmonic motion of amplitude A. At what distance from the mean position its kinetic energy is equal to its potential energy ?
0.51 A
0.61 A
0.71 A
0.81 A
A particle is subjected to two mutually perpendicular simple harmonic motions such that is x and y coordinates are given by The path of the particle will be:
A straight line
A circle
An ellipse
A parabola
A simple pendulum performs simple harmonic motion about x=0 with an amplitude a and time period T. The speed of the pendulum at will be:
A body is vibrating in S.H.M. with an amplitude of 0.06 m and frequency of 15 Hz. The maximum velocity and acceleration of the body are:
5.65 m/s, 5.32 x 102 m/s2
6.82 m/s, 7.62 x 102 m/s2
8.91 m/s, 8.21 x 102 m/s2
9.82 m/s, 9.03 x 102 m/s2
The frequency of a simple pendulum in a freely falling lift will be :
Zero
Infinite
Finite
Cannot say
A linear harmonic oscillator of force constant 2 x 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Which of the following statement is true ?
Maximum potential energy is 160 J
Maximum potential energy is 100 J
Maximum potential energy is zero
Minimum potential energy is 100 J
A particle moving along the X-axis executes simple harmonic motion; then the force acting on it is given by:
-AKx
A cos Kx
A exp(-Kx)
AKx
Two springs of spring constants k1and k2 are joined in series. The effective spring constant of the combination is given by:
k1 + k2
A particle, with restoring force proportional to displacement and resisting force proportional to velocity is subjected to a force F sin. If the amplitude of the particle is maximum for =1, and the energy of the particle is maximum for = 2, then:
1 = 0 and 2 0
1 = 0 and 2 = 0
1 0 and 2 = 0
1 0 and2 0
