A particle has simple harmonic motion. Its equation of motion is :cm where x is the displacement. If the displacement of the particle is 3 cm, then its velocity in cm/s is :
20
16
The angular velocity and the amplitude of a simple pendulum is and respectively. At a displacement x from the mean position, if its kinetic energy is T and potential energy is U, then the ration of T to U is:
The total energy of a body performing S.H.M. depends on :
k,a,m
k,a,x
k,a
k,x
The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of oscillations is:
Two simple harmonic motions with the same frequency act on a particle at right angles ie, along X and Y-axis. If the two amplitudes are equal and the phase difference is , the resultant motion will be:
A circle
An ellipse with the major axis along y-axis
An ellipse with the major axis along x-axis
A straight line inclined at 45o to the x-axis
A particle moves such that its acceleration a is given by a = -bx where x is the displacement from equilibrium position and b is a constant. The period of oscillations is:
The frequency of a simple pendulum in a freely falling lift will be :
Zero
Infinite
Finite
Cannot say
The S.H.M. of a particle is given by the equation . The amplitude of motion is
7
12
1
5
The displacement x (in metres) of a particle performing S.H.M is related to time t (in second) as :
0.5 Hz
1.0 Hz
1.5 Hz
2.0 Hz
A mass m is suspended from a spring of negligible mass and the system oscillates with a frequency n. What will be the frequency of oscillations if a mass of 4 m is suspended from the same spring ?
2n
4n
