Two springs A and B have force constants KA and KB such that kB =2kA. The four ends of the springs are stretched by the same force. If the energy stored in spring A is E, then the energy stored in spring B is will be:
2E
E
4E
In SHM restoring force is F=-kx, where k is the force constant, x is displacement and a is the amplitude of motion, then total energy depends upon:
k,a and m
k,x,m
k,a
k,x
The displacement of a particle between maximum potential energy position and maximum kinetic energy position in simple harmonic motion is:
A body is vibrating in S.H.M. with an amplitude of 0.06 m and frequency of 15 Hz. The maximum velocity and acceleration of the body are:
5.65 m/s, 5.32 x 102 m/s2
6.82 m/s, 7.62 x 102 m/s2
8.91 m/s, 8.21 x 102 m/s2
9.82 m/s, 9.03 x 102 m/s2
Two simple harmonic motions given by, act on a particle simultaneously, then the motion of particle will be
Circular anticlockwise
Circular clockwise
Elliptical anticlockwise
Elliptical clockwise
A particle has simple harmonic motion. Its equation of motion is :cm where x is the displacement. If the displacement of the particle is 3 cm, then its velocity in cm/s is :
20
16
The acceleration of a particle in S.H.M. is:
Always constant
Maximum at extreme positions
Maximum at mean position
Always zero
A particle moving along the X-axis executes simple harmonic motion; then the force acting on it is given by:
-AKx
A cos Kx
A exp(-Kx)
AKx
A point performs simple harmonic oscillation of period T and the equation of motion is given by After the elapse of what fraction of the time period the velocity of the point will be equal to half of its maximum velocity ?
The S.H.M. of a particle is given by the equation . The amplitude of motion is
7
12
1
5
