If one factor of 8 x3+27 y3+18 xy-1 is (2 x+3 y - 1) then the other is
4 x2+9 y2+1
4 x2+9 y2-1
4 x2+9 y2+1 -6 xy+3 y+2 x
4 x2+9 y2+1 +6 xy-3 y-2 x
Factorize 1- 8 x+16 x2
(1-4 x)2
(1+4 x)2
(2-4 x)2
(1-8 x)2
(x - 4) (x + 3) =
x2 + x - 12
x2 - 7 x - 12
x2 + 7 x + 12
x2 - x - 12
(a+b)2- (a-b)2=
2 a2
2 b2
4 ab
8 ab
(x+a) (x+b)
x2+ab x+ab
x2+ (a+b)x+ ab
x2+(ab+b)x+ab
ax2+bx+ab
x2 - x - 20 =
(x+5) (x-4)
(x-10)2
(x+4)2
(x-5) (x+4)
Splitting of x- term in 3 x2- 11 x + 6 is
-11, -1
-9,-2
-5,-6
-7,-4
Factors of a4 + 4 are
(a2+2)2
(a2-2)2
(a2+2)(a2-2)
(a2+2 a+2)(a2-2 a+2)
Factors of x2+7 x+12 are
(x+5) (x+2)
(x+3) (x+4)
(x+6) (x+2)
(x+3)2
The expression (10.5 x 10.5 - 10.5 x 4.5+4.5 x 4.5) (10.5+4.5) is in the form of
(a+b)2
(a-b)2
a3-b3
a3+b3
