The number of terms of the A.P 3, 7, 11, 15--- to be take so that the sum is 406
5
10
12
14
If m, p, q are consecutive terms in an A.P, then P is
mq/2
m - q/2
m2+q2/2
m + q/2
The first 3 terms of the sequence an = n+1/n+2 is
5/4, 4/3, 3/2
2/3, 3/4, 4/5
4/5, 3/4, 2/3
4, 3, 2
If G is geometric mean of numbers a and b then G =
√ab
±√ab
ab
a/b
1 + 2 + 3 +........30 =
465
930
900
500
The sum to the first 25 terms of the series 1 + 2 + 3......... is
305
325
315
335
How many terms of the G.P 3, 3/2, 3/4......... are needed to give the sum 3069/512?
11
9
8
If the nth term of an AP is 6n - 1. Then its (n + 1)th term is __________
6n + 4
6n + 5
6n - 4
6n - 5
The income of a person is 3,00,000 in the first year and he receives an increase of Rs. 10,000 to his income per year for the next 19 years. Then the total amount, he received in 20 years is
80,00,000
79,00,000
78,00,000
69,00,000
If the sum of n terms of an A.P is (Pn + qn2) where p and q are constants. Then the common difference is
2 + q
2q
2/q
2 - q
