If the sum of 3 numbers in A.P is 24 and their product is 440, then the numbers are
5, 8, 11
6, 9, 12
7, 10, 13
4, 8, 12
The first 3 terms of the sequence an = n+1/n+2 is
5/4, 4/3, 3/2
2/3, 3/4, 4/5
4/5, 3/4, 2/3
4, 3, 2
How many terms of the G.P 3, 32, 33,...... are needed to give the sum 120?
4
5
6
18
How many terms of the G.P 3, 3/2, 3/4......... are needed to give the sum 3069/512?
10
11
9
8
Which term of the G.P, 2, 8, 32.......... up to n term is 131072?
8th term
9th term
7th term
6thterm
If m, p, q are consecutive terms in an A.P, then P is
mq/2
m - q/2
m2+q2/2
m + q/2
Sum of the sequence 9, 99, 999, 9999 up to n terms is
(10n -1) - n
9/10 (10n - 1) - n
10/9 (10n - 1) - n
None of these
The nth term of G.P 5, 25, 125 is
5n
5n-1
5n+1
n5
Given an = (n+1)2/n then a7 is
64
67
49/8
64/7
The A.M between pth and qth terms of an A.P is equal to the AM between rth and sth terms of the A.P. Then p+q =
r + s
r - s/r + s
r + s/r - s
r + s + 1