In screw guage, the index line is divided into some equal divisions. This serves as the
Pitch scale
Ordinary scale
Head scale
None of these
Find the Least count of screw gauge whose head scale is divided into 200 divisions and pitch of the screw is 1 mm?
0.05 mm
0.05 cm
0.0005 cm
0.005 cm
While measuring the diameter of a lead shot using a screw gauge,the reading on the pitch scale is found to be 7.5 mm and that on the head scale is 48. If the least count is 0.01 mm,the diameter of the lead shot is
0.798 mm
7.98 mm
0.0798 mm
0.00798 mm
Pitch of the screw x No of revolution made =
distance travelled
displacement
CHSR
PSR
If the zeroth division of the head scale is below the index line ,the error is said to be positive and the correction is
Negative
Positive
Neutral
When a screw gauge of Least count 0.01 mm is used to measure the diameter of a nail, the P.S.R. is found to be 1.5 mm, and H.S.R is 18. Find the diameter of the nail ?
0.0168 mm
16.8 mm
0.168 mm
1.68 mm
The value of the head scale division which just coincides with the reference line is observed as
Head Scale Reading
Ordinary Scale Reading
Pitch Scale Reading
Corrected Head Scale Reading
Equation for pitch of the screw is, p =
p = x / n
p = xn
p = n / x
p = n2x
In screw gauge the barrel is tapered and has 100 or 50 equal divisions on it. This is called the
Least count
Pitch of the screw is 1 mm. Head scale has 100 divisions. Give the Least Count.
0.0001 m
1 m
0.00001 m
.001 m