Consider points A,B,C and D with position vector respectively. Then, ABCD is a.
Square
Rhombus
Rectangle
None of these
The position vectors of P and Q are respectively and . If R is a point on such that , then the position vector of R is
The non-zero vectors Then, the angle between is.
π
0
π/4
π/2
Let and , are non - zero and non- collinear vectors. If there exists scalars α, β such that α + β = , then
α = β ≠ 0
α + β = 0
α = β = 0
α = β
If then angle between and is
π/6
π/3
If C is the midpoint of AB and P is any point outside AB, then
If the position vector of A with respect to O is then the position vector of B with respect to 0 is
The resultant of
√29
√66
4
√62 - 2 √35
If = (1,-1) and = (-2, m) are two collinear vectors, then m is equal to
2
1
Two vector and of equal magnitude 5, originating from a point and directs respectively towards north east and north- west. Then, the magnitude of - is
3√2
2√3
2√5
5√2
