If tan θ = 5/12, then sec θ =
10/24
25/144
13/12
15/14
If 2 sin θ = √3, then cos θ =
√3/2
2/√3
1/2
2
1/cos θ =
sin θ
cosec θ
sec θ
tan θ
1/5
1/3
3/5
5/4
If 5 cos A - 12 sin A = 0, then the value of is
17/12
17/19
19/12
19/17
cot θ =
cos θ/ sinθ
1/cos θ
sin θ/cosθ
1/sec θ
In Δ PQR,∠ Q = 90o, PQ = 4 cm and PR = 9 cm, then the value of sinP is
10/9
√95/9
√65/9
√17/4
cosec 74 + tan 81 equal to
sec18 + cot 10
sec17+ cot 11
sec16 + cot 9
sec19+ cot 12
In the figure find sin (90o - θ )
4/5
5/3
If sec θ = 2 then sin θ =
3/2
1/√3
