In the figure find sin (90o - θ )
4/5
3/5
5/3
5/4
If sec θ = 2 then sin θ =
1/2
3/2
1/√3
√3/2
If cosec θ = √2, then cot θ =
0
1
√2 + 1
√2 - 1
If sec θ = √3, then sin θ + cos θ =
√2
√6 + √3
If 5 cos A - 12 sin A = 0, then the value of is
17/12
17/19
19/12
19/17
If 5 sin θ = 3 then tan θ =
1/4
3/4
1/5
1/cos θ =
sin θ
cosec θ
sec θ
tan θ
In Δ PQR,∠ Q = 90o, PQ = 4 cm and PR = 9 cm, then the value of sinP is
10/9
√95/9
√65/9
√17/4
If 2 sin θ = √3, then cos θ =
2/√3
2
cosec 74 + tan 81 equal to
sec18 + cot 10
sec17+ cot 11
sec16 + cot 9
sec19+ cot 12
