sin2 50+ cos2 50 =
1
0
1.25
2.32
In right triangle Δ ABC, ∠ B = 90o, tan C = 1/2. If AC = 6 cm, then AB =
6/√5 cm
2 cm
3/√5 cm
√5 cm
If 2 sin θ = √3, then cos θ =
√3/2
2/√3
1/2
2
cot θ =
cos θ/ sinθ
1/cos θ
sin θ/cosθ
1/sec θ
If 5 sin θ = 3 then tan θ =
1/4
3/4
3/5
1/5
In Δ PQR,∠ Q = 90o, PQ = 4 cm and PR = 9 cm, then the value of sinP is
10/9
√95/9
√65/9
√17/4
In the figure find sin (90o - θ )
4/5
5/3
5/4
1/3
If 5 cos A - 12 sin A = 0, then the value of is
17/12
17/19
19/12
19/17
If sec θ = √3, then sin θ + cos θ =
√2
√6 + √3