10 g of ice at 0 °C absorbs 5460 J of heat energy to melt and change to water at 50 °C. Calculate the specific latent heat of fusion of ice.
436 J g-1
336 J g-1
546 J g-1
420 J g-1
The change from soild to vapour directly at a constant temperature is called:
Condensation
Sublimation
Regelation
Vaporisation
How much heat is released when 5 g of water at 20 °C changes into ice at 0 °C?
210 J
5460 J
2000 J
2100 J
From the following which is the principle of mixtures ?
Heat energy lost by the hot body = Heat energy gained by the cold body
Heat energy lost by the cold body = Heat energy gained by the hot body
Heat energy gained by the hot body = Heat energy lost by the cold body
Both (2) and (3)
Calculate the amount of heat energy required to raise the temperature of 100 g of copper from 20 °C to 70 °C?
195000 J
1950 kJ
1950 J
19500 kJ
Due to the presence of salt in ice the melting point.
Increase from 0 to -22°C
Decreases from 0 to -22°C
Increase from 0 to 22°C
Decreases from 22 to 0°C
The reverse change from liquid to solid phase with rejection of heat at a constant temperature is called
melting
fusion
freezing
boiling
From the following choose the correct statement.
(a) 10 kg of water and 10000 gm of copper requires same amount of heat to raise their temperature through 1 °C.(b) 5 litre of water and 50 litre of water requires same amount of heat to raise their temperature through 1 °C.(c) 50 gm of copper and 500 gm of copper requires same amount of heat to raise their temperature through 1 °C.(d) 60 kg of water and 60000 kg of water requires same amount of heat to raise their temperature through 1 °C.
Both (a) and (c)
Only (a)
Only (d)
Only (c)
What is the latent heat of fusion of mercury?
180 x 103 J kg-1
3 x 103 J kg-1
21 x 103 J kg-1
12.5 x 103 J kg-1
The specific heat capacity of aluminium is 1.2 cal/g/°C.Its value in J/kg/K will be:
5.04 x 103
1.2 x 103
4.2 x 103
3.5 x 103