ABC is an isosceles right triangle, right angled at C, then AB2=
AC2
3 AC2
2 AC2
1/2 AC2
Δ ABC~ ΔPQR then AB: PQ=
QR: BC
AC:PR
PR:AC
RQ:AB
4.5
3
3.6
2.4
In ΔABC, B=90o; if AC= m; BC=n; then AB=
√(m2+n2)
m+n
m2-n2
√(m2- n2)
If two triangles are congruent, they have
the same shape
the same size
the same size and the same shape
no similarity
ΔABC ~ΔPQR; If AB = 6; BC = 4; AC = 8 and PR = 6; then PQ + QR =
7.5
8.5
9
10.5
The triangle with sides m2+n2, m2-n2, 2 mn is
Isosceles
Right angled isosceles
Right angled
Equilateral
The area of an equilateral triangle of side a cm is
(√3/ 4) a2
(1/2) a2
(√3/2 )a3
(√3/2 )a
Given MN|| BC; ΔABC and ΔANM are
Non -similar
Congruent
Equal in area
Similar
ΔABC ~ΔPQR; If AB =3.6, PQ= 2.4 and PR= 5.4, then AC=
8.1
5.4
7.8