The A.M between pth and qth terms of an A.P is equal to the AM between rth and sth terms of the A.P. Then p+q =
r + s
r - s/r + s
r + s/r - s
r + s + 1
If the sum of n terms of an A.P is (Pn + qn2) where p and q are constants. Then the common difference is
2 + q
2q
2/q
2 - q
1 + 2 + 3 +........30 =
465
930
900
500
Which term of the G.P, 2, 8, 32.......... up to n term is 131072?
8th term
9th term
7th term
6thterm
If the nth term of an AP is 6n - 1. Then its (n + 1)th term is
6n + 4
6n + 5
6n - 4
6n - 5
The sum to the first 25 terms of the series 1 + 2 + 3......... is
305
325
315
335
Sum of the sequence 9, 99, 999, 9999 up to n terms is
(10n -1) - n
9/10 (10n - 1) - n
10/9 (10n - 1) - n
None of these
The value of 112 + 122 + .....202 is
3845
2485
2470
3255
How many terms of the G.P 3, 32, 33,...... are needed to give the sum 120?
4
5
6
18
The 10th term of an A.P is 52 and 16th terms is 82. Then the 32nd term is
162
165
173