x^{2} -3 |x| + 2 < 0, then x belongs to
( 1,2 )
( -2, -1 )
( -2, -1 ) U ( 1, 2 )
( -3, 5 )
Consider the following system of inequalities 5x + 3y ≥ 0 and y -2x < 2. The solution of the above inequalities does not contain only part of the
First quadrant
Second quadrant
Third quadrant
Fourth quadrant
|3x + 7 | < 5, then x belongs to
( -4, -3 )
( -4, ^{-2}/_{3} )
(-5, 5)
( ^{-5}/_{3}, ^{5}/_{3} )
The set of values of x satisfying the inequalities ( x -1 ) ( x -2 ) < 0 and ( 3x - 7 ) ( 2x - 3 ) > 0 is
(1, 2 )
( 2, ^{7}/_{3} )
( 1, ^{7}/_{3} )
( 1, ^{3}/_{2} )
If a > b then
a + 5 > b + 5
a - b < b - 5
a + b < b + b
Depends on a and b
|x + ^{2}/_{x} | < 3, then x belongs to
(-2,-1) U ( 1,2 )
(-∞, -2 ) U (-1, -1) U ( 2, ∞ )
(-2, 2 )
(-3, 3 )
If^{ 1}/_{a} < ^{1}/_{b}; then
| a | > | b |
a < b
a > b
None of these
( x - 1 ) > 0
( x -2 ) > 0
(x - 2 ) < 0
( x - 1 ) > 0 if ( x -2 ) > 0
If 3 < 3 t - 18 ≤ 18, then which one of the following is true?
15 ≤ 2 t+1 ≤ 20
8 ≤ 2 t ≤ 12
8 ≤ t+1 ≤ 13
21≤ 3 t ≤ 24
Log_{ 2} x > 4, then x belongs to
x > 4
x > 16
x > 8