If A B and C D then A × C
B
D
B × D
D × B
Let A be a non-empty set such that A × B = A × C.Then.
A = C
A = B
B = C
A × B = C × C
The relation R defined on the set A = {1,2,3,4,5} by R = {(x,y) : < 16} is given by.
{(1,1),(2,1),(3,1),(4,1),(2,3)}
{(2,2),(3,2),(4,2),(2,4)}
{(3,3),(4,3),(5,4),(3,4)}
None of these
A = {1,2,3,4,5} and B = {4,6,9}. A relation R from A to B defined by R = {(x,y) : the difference between x and y is odd, x A,y B}.Write R in Roster form.
{(1,4) (1,6) (2,9),(3,4) ,(3,6) (5,4), (5,6)}
{(4,1),(6,2),(9,3),(4,3),(6,3),(4,5),(6,5)}
{(1,4),(2,6 ) (2,9),(3,4) (3,6),(5,4) (5,6)}
The relation R defined by R = {(x,x+5) : x {0,1,2,3,4,5}.The range of R is
{1,2,3,4,5}
{6,7,8,9,10}
{5,6,7,8,9}
{5,6,7,8,9,10}
If A B,then A × A =
B × B
(A × B) (B × A)
(A × A) (B × B)
If A and B are any two non-empty sets then if A × B = B × A then
A ≠ B
A = 2B
If A × B = {(a,x),(a,y),(b,x),(b,y)}.Find A and B?
A = {a,b}
B = {x,y}
A = {a,x}
B = {b,y}
A = {x,y}
B = {a,b}
The relation R defined by R = {(x,x+5) : x {0,1,2,3,4,5}.The domain of R is
{1,2,3}
{0,1,2,3,4,5}
R is a relation from {11,12,13} to {8,10,12} defined by y = x - 3 .The relation R-1 is.
{(11,8),(13,10)}
{(8,11),(10,13)}
{(8,11),(9,12),(10,13)}
