The marks obtained in chemistry by the 15 students of class XI B are
20, 15, 10, 20 27, 28, 27, 10, 20, 30 35, 40, 41, 41, 20 then the value of mode is
10
20
27
41
If 96 is the variance of the scores of a batsman in matches played by him. Then the standard deviation is
6.87
9.79
9.98
10.9
Geometric means of 2, 22, 23, . . . . . 2n is
22/n
2n/2
2n
2(n+1)/2
The median of the observations 2, 30, 12, 25, 20, 8, 10, 4, 15, Is
12
25
15
The mean of 5 numbers is 18. If one number is excluded, their mean becomes 16, then the excluded number is
18
26
30
If 10 is the mean of a set of 7 observation and 5 is the mean of a st of 3 observations, then the mean of the combined set is
8.5
7.5
The heights ( in cm ) of the 15 students of a class are 152, 145, 156, 149, 151, 159, 148, 160, 153, 154, 150, 143, 155,
157, 161 cm. The median of height of the student is
152 cm
149 cm
153 cm
150 cm
One of the method of determining mode is
Mode = 2 median - 3 mean
Mode = 2 median + 3 mean
Mode = 3 median - 2 mean
Mode = 3 median + 2 mean
The variance of first n natural numbers is
The mean deviation from the observations 3, 8, 12, 19, 20 is
6.5
7.9
9.7